(6u^2-96)/(u^2+2u-24)=0

Solution for (6u^2-96)/(u^2+2u-24)=0 equation:

(6u^2-96)/(u^2+2u-24)=0


Domain of the equation: (u^2+2u-24)!=0

We move all terms containing u to the left, all other terms to the right

u^2+2u!=24

u∈R


We multiply all the terms by the denominator


(6u^2-96)=0

We get rid of parentheses

6u^2-96=0

a = 6; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·6·(-96)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*6}=\frac{-48}{12}
=-4
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*6}=\frac{48}{12}
=4
$